Form a polynomial whose zeros and degree are given. Zeros: -7, multiplicity 1 3;multiplicity 2; degree 3

Type a polynomial with integer coefficients and a leading coefficient of 1 in the box below.

The polynomial is x^3-x^2-33x+63

Step-by-step explanation:

Here, we want to find a polynomial of degree 3 with the given roots

-7 with a multiplicity of 1 and 3 with a multiplicity of 2

if x = -7

x + 7 is a root

if x = 3

x -3 is a root

Since the multiplicity of this is 2, we have x-3 twice

The complete polynomial is;

(x-3)(x-3)(x+7)

= x^2-6x+9(x + 7)

= x(x^2-6x+9) + 7(x^2-6x+9)

= x^3-6x^2 + 9x+7x^2-42x+63

= x^3-x^2-33x+63

the correct answer is 5

step-by-step explanation:

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