A fair spinner has 10 equal sections. A
A
B
B
C
A
A

Put a cross on the scale to show the probability of landing on the letter A.

there would be a possibility

Step-by-step explanation:cuz ratio form would be A:B:C

(4:2:1)

BRACKETS IS WHET U NEED TO LOOK AT

75

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)