Mathematics, 29.11.2020 17:30 olson1312

Solve the following pair of equations simultaneously. See image for question
Answer question (III)

Solve the following pair of equations simultaneously.

See image for question
Answer question (II

Answers: 3

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Answer from: Anikarenee

No solutions.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDASEquality Properties

Algebra I

Solving systems of equations using substitution/eliminationSolving systems of equations by graphingExpandingFinding roots of a quadraticStandard Form: ax² + bx + c = 0Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define systems

2x - y = 9

4x² + 3y² - 2x + y = 16

Step 2: Rewrite systems

2x - y = 9

Subtract 2x on both sides: -y = 9 - 2xDivide -1 on both sides: y = 2x - 9

Step 3: Redefine systems

y = 2x - 9

4x² + 3y² - 2x + y = 16

Step 4: Solve for x

Substitution

Substitute in y: 4x² + 3(2x - 9)² - 2x + (2x - 9) = 16Expand: 4x² + 3(4x² - 36x + 81) - 2x + (2x - 9) = 16Distribute 3: 4x² + 12x² - 108x + 243 - 2x + 2x - 9 = 16Combine like terms: 16x² - 108x + 234 = 16Factor GCF: 2(8x² - 54x + 117) = 16Divide 2 on both sides: 8x² - 54x + 117 = 8Subtract 8 on both sides: 8x² - 54x + 109 = 0Define variables: a = 8, b = -54, c = 109Resubstitute: $x=\frac{54\pm\sqrt{(-54)^2-4(8)(109)} }{2(8)}$ Exponents: $x=\frac{54\pm\sqrt{2916-4(8)(109)} }{2(8)}$ Multiply: $x=\frac{54\pm\sqrt{2916-3488} }{16}$ Subtract: $x=\frac{54\pm\sqrt{-572} }{16}$

Here we see that we start to delve into imaginary roots. Since on a real number plane, we do not have imaginary roots, there would be no solution to the systems of equations.

Step 5: Graph systems

We can verify our results.

Solve the following pair of equations simultaneously.

See image for question
Answer question (III)

Answer from: Quest

can someone answer this question plz

step-by-step explanation:

Answer from: Quest

If your asking how much altogether for 12 performance the answer will be 98,496.

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Solve the following pair of equations simultaneously. See image for question
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