A man, a woman, and their four children randomly stand in a row for a family picture. What is the probability that the parents will be standing next to each other?

The probability that the parents will be standing next to each other is 2/11

Probability is the likelihood or chance that an event will occur.

Given a woman, man and their four children, if their parents will be standing next to each other, that makes it 5 people. The sample space for 5 people is 11!

Pr(parents standing next to each other) =  2!10!/11!

Pr(parents standing next to each other) = 2*10!/11*10!

Pr(parents standing next to each other) = 2/11

Therefore the probability that the parents will be standing next to each other is 2/11

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Required probability = 2 / 11

Step-by-step explanation:

Sample space of 5 person = 11!

One woman one man arrangement = 2!

Arrangement without woman = 10!

Required probability = [2!][10!] / [11!]

Required probability = 2 / 11

for a it would be 24 children.

for b i don't understand the question. is it saying for each individual person they pick 5 reds to 7 greens or is it the whole group. clarify and i hope this can you.

step-by-step explanation: