Factorise 18a^2x^2 - 32
Please solve this fast.

18a²x² - 32

= 2 (9a²x² - 16)

= 2 {(3ax)² - 4²}

= 2 (3ax + 4) (3ax - 4),

[using the identity

a² - b² = (a + b) (a - b)]

which is the required factorization.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

i need points

step-by-step explanation:

sorry bubs