Question The average number of acres burned by forest and range fires in a county is 4,500 acres per year, with a standard deviation of 780 acres. The distribution of the number of acres burned is normal. What is the probability that between 3,000 and 4,800 acres will be burned in any given year? Round your answer to four decimal places. Provide your answer below:

The probability that between 3,000 and 4,800 acres will be burned in any given year is 0.6206

Step-by-step explanation:

Given

Mean = μ = 4500 acres

SD = σ = 780 Acres

Two data points between which the probability has to be calculated are:

3000 and 4800

x1 = 3000

x2 = 4800

z-score will be found for both data points

z-score is given by the formula

The z-scores are:

Now we have to find probabilities for both z-scores using the z-score table

Now for the probability between both values

Rounding off to four decimal places

0.6206

Hence,

The probability that between 3,000 and 4,800 acres will be burned in any given year is 0.6206

you would need to know all the numbers that are on there

step-by-step explanation:

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.