triangle ABC has vertices at A (-12,-8) B (10,-6) and C (6,14. What is the midpoint of side AC of the triangle?

Step-by-step explanation:

midpoint of AC=(x¹+x²/2,y¹+y²/2)

=(-12+6/2,-8+14/2)

=(-6/2, 6/2)

=(-3,3)

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

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step-by-step explanation: