PLEASE HELP (PICTURE INCLUDED) Which triangle is similar to triangle PQR using the Pieces of Right Triangles Similarity Theorem?

Triangle SRP has measure of angle SRP equal to 90 degrees. Q is a point on the hypotenuse SP such that the segment QR is perpendicular to PS. T is a point outside the triangle on the left of S so that triangle QTS has the measure of angle QTS equal to 90 degrees.

Triangle RQS
Triangle TSQ
Triangle QST
Triangle SRQ

Triangle RQS will be the correct one I think

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a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²