If the first and fifteen terms of A. P. are 8 and -48 respectively, obtain the progression

8, 4, 0, -4, - 8, .........

Step-by-step explanation:

The n the term of an AP is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 8 and a₁₅ = - 48, then

8 + 14d = - 48 ( subtract 8 from both sides )

14d = - 56 ( divide both sides by 14 )

d = - 4

To obtain the progression subtract 4 from each term, that is

8, 4, 0, - 4, - 8, ......

8, 4, 0, -4, -8, -12, -16, -20,...

Step-by-step explanation:

Arithmetic Progressions

The general term of an arithmetic progression (A.P.) is:

Where:

a1  = First term

an = Term number n

n   = Number of the term

r   = Common difference

We are given: a1=8, and a15=-48, n=15. Calculate r:

r = -4

We can get the terms of the progression by subtracting 4 to the previous term.

Thus, the first terms of the progression are:

8, 4, 0, -4, -8, -12, -16, -20,...

homozygous. one is homozygous, while two is heterozygous.

the answer would be c:   ax + b = ax + c

step-by-step explanation: