Anyone out there can solve this I will give 17 points!!! Lauren is twice Kristy’s age. The sum of Lauren and Kristy’s ages is 51. Which equation represents the sum of their ages?
A K + K + 2 = 51 B K + 2K + 2 = 51 C 2K = 51 D K + 2K = 51

D. K+2K=51

Step-by-step explanation:

Since Lauren is 2 times Kristy's age, Lauren's age=2K

so, if the sum of the two is 51, then 2K+K=51

If you want to solve it, 2K+K=3K=51

51/3=K

17=K

34=L

D K + 2K = 51

Step-by-step explanation:

Lauren is twice Kristy's age so it would be 2K cause you want to multi[ly, and then you have to add Kristy's age in the equation because their ages added together is 51

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all