3. CONSTRUCTION A rectangular deck is built around a square pool. The pool has side length s. The

length of the deck is 5 units longer than twice the side

length of the pool. The width of the deck is 3 units

longer than the side length of the pool. What is the

area of the deck in terms of s?

Did I do this right or was I supposed to leave it as a trinomial?

Area of the deck in terms of s is  

Step-by-step explanation:

The pool side length = s

Length of the deck  = 5 +2s

Width of the deck = 3 + s

Area of the deck = Length  * width  ( as the deck is rectangle)

                       = (5 + 2s)(3+s) =

                  Area =

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source