Using a Table of Values to Find a Solution to a System a) Complete the table below to solve the equation 2.5x-10.5=64(0.5)x.

x f(x)=2.5x-10.5 g(x)=64(0.5)x
2
3
4
5
6

b) Give the solution for the equation:

This problem wants you to substitute the answers from the table into the equation to find the solution, which is when the input gives the same output basically.

f(x) = 2.5x -10.5                          g(x) = 64(0.5)^x

when x= 2...                                when x= 2...

f(2) = 2.5(2) - 10.5                        g(2) = 64(0.5)^2

f(2) = 5 - 10.5 = -5.5                     g(2) = 64(.25)= 16

when x= 3...                                 when x= 3...

f(3) = 2.5(3) - 10.5                         g(3) = 64(0.5)^3

f(3) = 7.5 - 10.5 = -3                      g(3) = 64(0.125) =8

when x= 4...                               when x = 4...

f(4) = 2.5(4) - 10.5                       g(4) = 64(0.5)^4

f(4) = 10 - 10.5 = -0.5                  g(4) = 64(0.0625) = 4

when x= 5...                               when x= 5...

f(5) = 2.5(5) - 10.5                      g(5) = 64(0.5)^5

f(5) = 12.5 - 10.5 = 2                   g(5) = 64(0.03125) = 2

when x= 6...                               when x = 6...

f(6) = 2.5(6) - 10.5                       g(6) = 64(0.5)^6

f(6) = 15 - 10.5 = 4.5                   g(6) = 64(0.015625) = 1

14

step-by-step explanation:

14 x 3 = 42

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15