A projectile is launched from ground level with an initial velocity of v 0

v0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by

s equals negative 16 t squared plus v 0 t

s=−16t2+v0t. Find the time(s) that the projectile will (a) reach a height of

288

288 ft and (b) return to the ground when

v 0

v0

equals

=

144

144 feet per second.

you forgot an image

step-by-step explanation:

d

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

a

step-by-step explanation: