What is the value of x if a² + ax - 10 is divided by a-2?

help with computation po

x = 3

Step-by-step explanation:

We need it in factorized form to get x.

If the quadratic equation can be divided by a-2 the first part is:

(a-2)

Now to get a², the a must be multpilied by itself. So

(a-2)(a)

To get -10, -2 must be multiplied by 5. So:

(a-2)(a+5)

we can expand to get x

a² + 5a - 2a -10

a² + 3a - 10

a² + ax - 10

x = 3

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^