Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.

a : b = 4 : 3

Step-by-step explanation:

(mark as brainlist answer)

According to the given condition is the question :

Two numbers a and b are such that the sum of 5% of a and 4% of b is two-third of the sum of 6% of a and 8% of b

⇒ (5% of a) + (4% of b) = (2/3) × [(6% of a) + (8% of b)

⇒ 0.05a + 0.04b = 2/3 × (0.06a + 0.08b)

⇒ 0.15a + 0.12b = 0.12a + 0.16b

⇒ 0.03a = 0.04b

⇒ a/b = 4/3

⇒ a : b = 4 : 3

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

mnkjn

step-by-step explanation: