A drawer of loose socks contains 2 red socks, 2 green socks, and 6 white socks. What best describes how to determine the probibility of pulling a white sock, not replacing it, then pulling out another white sock?

Probability = 1/3

Step-by-step explanation:

The drawer of loose socks contains 2 red socks, 2 green socks, and 6 white socks.

This is a total of 10 socks.

Probability of pulling a white socks = 6/10

Since it is not replaced, it means we have 5 white socks left out of a total of 9 now.

Probability of pulling out another white socks = 5/9

Thus;

The combined probability is;

6/10 × 5/9 = 30/90 = 1/3

3 is greater then both of those numbers

the answer is 150.6

step-by-step explanation:

you multiply .02 by 30 and get .6.

and then you multiply 5.00 by 30 and get 150.

hope this !