Suppose (ideally) a hammer claw moves a distance of 0.10 meters to remove a nail. If a resistance force of 1500 N is exerted by the claw, and you move the handle of the hammer 0.5 meters, what is the effort force?

7500 N

Step-by-step explanation:

Given that,

A hammer claw moves a distance of 0.10 meters to remove a nail.

Resistance force, F = 1500 N

The person move the handle of the hammer 0.5 m

We need to find the effort force. Let it is F'. The mechanical advantage is given by :

Where are input and output distance respectively.

So, the effort force is 7500 N.

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17