The radius, r cm, of a circle at time ts is given by r= t^3/3 -2, t> or = 0, find the rate at which the radius is changing when t=1 and t=2. PLEASE SOMEONE HELP

correct answers below:

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step-by-step explanation:

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus