Struggling.

x = - 3, x = - 2, x = 0

Step-by-step explanation:

Given

x³ + 5x² + 6x ← factor out x from each term

= x(x² + 5x +6) ← factor the quadratic

Consider the factors of the constant term (+ 6) which sum to give the coefficient of the x- term (+ 5)

The factors are + 2 and + 3 , since

2 × 3 = + 6 and 2 + 3 = + 5 , thus

x² + 5x + 6 = (x + 2)(x + 3) , and

f(x) = x³ + 5x² + 6x = x(x + 2)(x + 3)

To find the zeros equate f(x) to zero, that is

x(x + 2)(x + 3) = 0

Equate each factor to zero and solve for x

x = 0

x + 2 = 0 ⇒ x = - 2

x + 3 = 0 ⇒ x = - 3

Zeros from least to greatest are x = - 3, x = - 2, x = 0

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it

could you provide figure.