Mathematics, 26.11.2020 06:40 lkipjjjjjjjjjj5673
In triangle ABC, we can draw a perpendicular line segment from vertex C to segment AB. The intersection of AB and the perpendicular is called E. We know that BE is the shortest distance from B to and that is the shortest distance from A to CE because of the shortest distance theorem. Therefore, BC > BE and AC > AE. Next, add the inequalities: BC + AC > BE + AE. Then, BE + AE = BA because of the . Therefore, BC + AC > BA by substitution.
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If (x-2) 2= 49, then x could be a. -9 b. -7 c.- 2 d. 5 e.9
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Mathematics, 21.06.2019 21:00
If u good at math hit me up on insta or sum @basic_jaiden or @ and
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In triangle ABC, we can draw a perpendicular line segment from vertex C to segment AB. The intersect...
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