Find the exact values of the six trigonometric functions of 0

Complete question is;

Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4).

Sin θ = -4/√41

Cos θ = -5/√41

tan θ = 4/5

Cosec θ = (√41)/-4

Sec θ = (√41)/-5

Cot θ = 5/4

Step-by-step explanation:

Now, we are given the point (-5, -4)

These are x and y points.

They will form a triangle and we know that from pythagoras theorem;

x² + y² = r²

Where r is the distance between the point and the origin

Thus;

r² = (-5)² + (-4)²

r² = 25 + 16

r = √41

So, y is the opposite side of the triangle while x is the adjacent side with r being the hypotenuse.

Thus, the trigonometric ratios are;

Sin θ = opp/hyp = -4/√41

Cos θ = adj/hyp = -5/√41

tan θ = opp/adj = -4/-5 = 4/5

Cosec θ = 1/Sin θ = 1/(-4/√41) = (√41)/-4

Sec θ = 1/cos θ = 1/(-5/√41) = (√41)/-5

Cot θ = 1/tan θ = 1/(4/5) = 5/4

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

18.75 gallons

step-by-step explanation: