A composition of transformations maps ΔKLM to ΔK"L"M". Triangle K L M is rotated 270 degrees about point P to form Triangle K prime L prime M prime. Triangle K prime L prime M prime is shifted down and to the right to form triangle K double-prime L double-prime M double-prime. The first transformation for this composition is [], and the second transformation is a translation down and to the right. a 90° rotation about point L a 270° rotation about point L a 90° rotation about point P a 270° rotation about point P

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answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.