PLZZ HELP 1. Find the value of x and y.
2. In an A-figure house, the two congruent sides extend from the ground to form a 34° angle at the peek. What angle does each side form with the ground?

Problem 4

Note the markings at the top indicate that angle y represents half the angle BAC. In other words, we need 2 copies of angle y to make up angle BAC.

So we know that angle BAC = 2y

Due to the fact that triangle ABC is isosceles, we know that base angles B and C are congruent to 47.

Focusing on triangle ABC we have

So,

A+B+C = 180 for any triangle, the angles always add to 180

2y+47+47 = 180

2y+94 = 180

2y = 180-94

2y = 86

y = 86/2

y = 43

Turn your attention to triangle ABD.

Here we have

We'll use the same idea as above, that all angles add to 180, to get...

A+B+D = 180

y+47+x = 180

43+47+x = 180

x+90 = 180

x = 180-90

x = 90

Problem 5

Let x be the angle formed by the diagonal sides and the horizontal ground. This is considered the base angle because this triangle is isosceles.

We have two base angles x and the third angle up top is 34

x+x+34 = 180

2x+34 = 180

2x = 180-34

2x = 146

x = 146/2

x = 73

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

idk

step-by-step explanation: