A game room has a perimeter of 70 ft. The length is 5 more than twice the width. How many feet squared of new carpeting should be ordered?

A = 250 square ft

Step-by-step explanation:

Equations

Let's call:

x = width of the game room

The length is 5 more than twice the width, thus:

2x+5 = length of the game room

The perimeter of a rectangle is twice the sum of the width and the length:

P = 2( x + 2x + 5 )

And the perimeter is 70 ft:

2( x + 2x + 5 ) = 70

Operating:

2( 3x + 5 ) = 70

Dividing by 2:

3x + 5 = 35

Subtracting 5:

3x = 30

Dividing by 3:

x = 30 / 3

x = 10

The width is 10 ft and the length is 2(10)+5=25 ft

The area of the game room is:

A = 10 ft * 25 ft

A = 250 square ft

answer: ouch. thats difficult

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet