If two consecutive sides of a rhombus are represented by 3x - 6 and x + 14, then the
perimeter of the rhombus is
A. 10
B. 24
C. 72 D. 96

d. 96

Step-by-step explanation:

consecutive sides = 3x - 6 and x + 14

all sides of a rhombus are equal, therefore

3x - 6 = x + 14

-x           -x

2x - 6 = 14

     +6    +6

2x = 20

2       2

x = 10

substitute x in equation

3x - 6 = x + 14

3(10) - 6 = 10 + 14

30 - 6 = 24

24 = 24

perimeter of a rhombus = 4a

                                        = 4(24)

                                         = 96

hope this helps

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo