The length of a rectangular deck is 5 times its width. If the deck’s perimeter is 24 feet, what is the deck’s area?

20ft²

Step-by-step explanation:

Let the length = L

Let the width = W

Perimeter of a rectangle = 2L + 2W

Translating the word problem into an algebraic equation, we have;

L = 5W equation 1

2L + 2W = 24 equation 2

To find the width

Substituting equation 1 into equation 2, we have;

2(5W) + 2W = 24

10W + 2W = 24

12W = 24

W = 24/12

Width, W = 2 ft

To find the length;

Substituting the value of "W" into equation 1, we have;

L = 5W

L = 5*2

L = 10 ft

To find the area of the rectangle;

Area = LW

Area = 10*2

Area = 20 ft²

Therefore, the deck's area is 20 feet square.

answer: idk

step-by-step explanation: