Factors of x3 + 5x2 + 2x – 8.

Answer=0

Step-by-step explanation:

Roots of x3−5x2+2x+8=0 are {−1,2,4}.

Explanation:

As the coefficient of x3 in x3−5x2+2x+8=0 is 1,

One of the roots must be factor of 81=8 i.e. it can be ±1.±2,±4or±8.

As sum of coefficients (1−5+2+8=6≠0) is not zero, it is evident that 1 is not the root of x3−5x2+2x+8=0.

But −1 is a root as −1−5−2+8=0 and hence as per factor theorem (x+1) is a factor of x3−5x2+2x+8=0

Dividing x3−5x2+2x+8 by (x+1) we get

x3−5x2+2x+8=x2(x+1)

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{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1