One number is 10 more than another. The sum of twice the smaller plus three times the larger, is 55. What are the two numbers?

x(smaller)=4, y(bigger)=5

Step-by-step explanation:

(2x+3)*y=55

11*5=55

so, 2x+3=11

2x=8 after subtracting 3 from both sides

x=4 after dividing by 2 from both sides

y is then equal to 5 because 11y=55

divide both sides by 11, you get y=5, which means y>x, and y is the larger number.

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)