Drag each tile to the correct box. Not all tiles will be used. Arrange the systems of equations that have a single solution in increasing order of the x-values in their solutions.
2x + y = 10
x − 3y = -2
x + 2y = 5
2x + y = 4
x + 3y = 5
6x − y = 11
2x + y = 10
-6x − 3y = -2
→ →

6 , 2 , 5 , 7 , 4 , 1 , 3

Step by Step:

1) x - 3(10 - 2x) = -2

x - 30 + 6x = -2

7x - 30 = -2

7x = 28

x = 4

2) x + 2(4 - 2x) = 5

x + 8 - 4x = 5

-3x + 8 = 5

-3x = -3

x = 1

3) 5(18 - 4y) + y = 33

90 - 20y + y = 33

90 - 19y = 33

-19y = -57

y = 3

x = 18 - 4(3)

x = 18 - 12

x = 6

4) 8x + 4(13 - 2x) = 52

8x + 52 - 8x = 52

52 = 52

5) x + 3(-11 + 6x) = 5

x - 33 + 18x = 5

19x - 33 = 5

19x = 38

x = 2

6) -6(5 - 2y) - 3y = -2

-30 + 12y - 3y = -2

-30 + 9y = -2

9y = 28

y = 3

2x + 3(3) = 5

2x + 9 = 5

2x = -4

x = -2

7) 2x + 3(10+x) = 45

2x + 30 + 3x = 45

5x + 30 = 45

5x = 15

x = 3

Step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

the correct answer is d

hope this