Write an equation in slope-intercept form for the line that passes through (6,- 3) and is parallel to y = -2x + 4 *

Write an equation in slope-intercept form for the line that passes through (6,- 3) and is parallel to y = -2x + 4.

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Parallel lines are lines with the same slope but different y-intercept.

Slope-intercept form is written as y=mx+b, where m is the slope and b is the y-intercept.

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The given line is y=-2x+4. A line parallel to this would have the same slope, which is -2. To find the y-intercept, plug the point into an equation in point-slope form.

m is the slope, and since the slope is the same as the given line, m will be equal to 2.

The line is supposed to pass through a point, which is written as (x, y). In this line, it is supposed to pass (6, -3). x₁ will be the x value of the point, and y₁ will be the y value of the point. That means x₁ is 6 and y₁ is -3.

Substitute the values into the formula:

When subtracting a negative number from a number or variable, the sign will change, and the number will become positive.

Here is the new equation:

Distribute the 2 to everything in the parentheses. It will be 2 times x and 2 times -6. Remember that a positive number multiplied by a negative number is negative.

Positive(+) times(×) positive(+) = positive(+) Positive(-) times(×) negative(-) = negative(-) Positive(+) divided(÷) by positive(+) = positive(+) Positive(+) divided(÷) by negative(-) = negative(-)

Rewrite the equation:

Lastly, you need to move -3 to the other side, as slope-intercept form is written as y=mx+b. You can move it by adding three(+3) to both sides, which is simply doing the opposite of it(-3+3=0).

The answer to your question is .

Can you provide the tape diagram?

The mode of the numbers is 29.