The quadratic function f(x) has real coefficients. Given that f(3 - 2i) = 0, what must be the other solution to the equation f(x) = 0 ?

Option (C)

Step-by-step explanation:

Conjugate root theorem:

If (a - bi) is a root of a polynomial with real coefficients, then (a + bi) will be the other root.

By this theorem, if (3 - 2i) is one root of the quadratic function 'f', other root will be (3 + 2i).

Therefore, x = (3 + 2i) will be the other root.

Option (C) will be the answer.

i think its 7.6

if so your welcome