PLEASE HELP I will mark as Brainlist
1.simplify : (4b+5c)^2 - (4b-5c)^2

2.factorise: 75a^2 b^2 - 27x^2 y^2 and x^2-3x-20

3.find the square: (a+2b+3c)
find the root of (3x-4y)

4.solve: x-30% of x=RS.140

5.resolve into factors: x^4 - 16 y^4 b, x^2-9x+2.

6.A sick person has to take three types of medicine. He takes type -x in every 3hrs, type-y in every 4 hrs, type -z in every 6 hrs. if he takes all types of medicines at the same time at 6:00 am, at what time does he take all these types of medicine, again at time?

Step-by-step explanation:

hey how u type that much

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2