In July in Virginia, the temperature can quickly rise above 90 degrees Fahrenheit, which can also lead to thunderstorms. The probability that the temperature will rise above 90 on a randomly chosen day is 0.68, and the probability of thunderstorms is 0.29. If the temperature rises above 90 degrees, the probability of a thunderstorm is 0.56. What is the probability that the temperature rises above 90 degrees and there is a thunderstorm on a randomly chosen day in July?

0.16
0.20
0.29
0.38

The probability that the temperature rises above 90 degrees and there is a thunderstorm on a randomly chosen day in July = 0.38

So, Option D is correct.

Step-by-step explanation:

The probability that the temperature will rise above 90 on a randomly chosen day = 0.68

The probability of thunderstorms= 0.29

If the temperature rises above 90 degrees, the probability of a thunderstorm = 0.56

We need to find the probability that the temperature rises above 90 degrees and there is a thunderstorm on a randomly chosen day in July?

So, the probability can be found by multiplying the probability that the temperature will rise above 90 on a randomly chosen day with if the temperature rises above 90 degrees, the probability of a thunderstorm

i.e

the probability that the temperature rises above 90 degrees and there is a thunderstorm on a randomly chosen day in July = 0.68 x 0.56 = 0.38

So, Option D is correct.

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

b and c are the correct answers.

good luck on the quiz! : d