What is the value of k that makes the equation (4x^2y^2+5xy+k)+(kx^2y^2-2xy-6)=7x^ 2+kxy-3

k=7x^(2)-4x^(2)y^(2)-3xy+3

          x^(2)y^(2)-xy

pretend the underline is like the line for a fraction/ division

Step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.