A parallelogram with coordinates A (-2,3), B (3,3), C (4,6), and D(-1,6) is the first rotated 90 degrees clockwise and then translated 4 units left and 2 units down to form quadrilateral A'B'C'D what is the distance, in units between point C' and point D' in the resulting figure

Given:

The vertices of a parallelogram are A (-2,3), B (3,3), C (4,6), and D(-1,6).

It is first rotated 90 degrees clockwise and then translated 4 units left and 2 units down to form quadrilateral A'B'C'D.

To find:

The distance between C' and D'.

Solution:

If a figure rotated 90 degrees clockwise, then

If figure translated 4 units left and 2 units down, then

Distance formula:

Distance between C'(2,-6) and D'(2,-1) is

Therefore, the distance between C'D' is 5 units.

the answer is 150.6

step-by-step explanation:

you multiply .02 by 30 and get .6.

and then you multiply 5.00 by 30 and get 150.

hope this !

question: use the following table of a school bus during morning pickups to calculate its average speed between 2.8 km and 4.2 km

answer: 42 km/h

explanation: 1.4/0.033 42.42424 = 42 km/h

question answered by

(jacemorris04)