CD and EF are parrellel to AB. They divide the area of triangle PAB into three equal parts. If PE=1, what is AC?

AC is approximately 0.3178

Step-by-step explanation:

The given parameters are;

In ΔPAB

CD ║ EF ║ AB

The area of triangle ΔPEF = 1/3 × area of triangle ΔPAB

Therefore, PE = 1/√3·PA

PA = √3

We have area of ΔPCD = 2/3 × area of triangle ΔPAB

∴ PC = √(2/3) × PA = √(2/3) × √3

PC = √2

Therefore, AC = PA - PC = √3 - √2

AC = √3 - √2 ≈ 0.3178

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step-by-step explanation:

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