Find the value of y so that y + 3, 4y + 1, 8y - 3 is an arithmetic progression.
A. 2
B. 3
C. 4
D. 5
E. 6

A

Step-by-step explanation:

The common difference d in an arithmetic sequence is

a₂ - a₁ = a₃ - a₂ , substitute values

4y + 1 - (y + 3) = 8y - 3 - (4y + 1) ← distribute both sides and simplify

4y + 1 - y - 3 = 8y - 3 - 4y - 1

3y - 2 = 4y - 4 ( subtract 3y from both sides )

- 2 = y - 4 ( add 4 to both sides )

2 = y → A

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

56

step-by-step explanation: