Consider the line that passes through each pair of given points, and decide what type of slope the line has. (2, 4) and (5, 1)
undefined slope
(3,5) and (-1,2)
negative slope
(-7, 8) and (-7,0)
positive slope
(6.-3) and (4, -3)
zero slope

The slope of line through (2, 4) and (5, 1) is Negative

The slope of line through (3,5) and (-1,2) is Positive

The slope of line through (-7, 8) and (-7,0) is Undefined

The slope of line through (6.-3) and (4, -3) is Zero

Step-by-step explanation:

Slope is defined as the steepness of a line.

Slope is denoted by m and the formula for calculating slope is:

Here

(x1,y1) and (x2,y2) are coordinates of the points through which the line passes

Now,

For (2, 4) and (5, 1):

NEGATIVE

For (3,5) and (-1,2)

POSITIVE

For (-7, 8) and (-7,0)

UNDEFINED

For (6.-3) and (4, -3)

ZERO

Hence,

The slope of line through (2, 4) and (5, 1) is Negative

The slope of line through (3,5) and (-1,2) is Positive

The slope of line through (-7, 8) and (-7,0) is Undefined

The slope of line through (6.-3) and (4, -3) is Zero

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497