Write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5, 0) ; y+1=2(x-3) A. y=-1/2x+5

B. y=2x-5

C. y=1/2x-2

D. y=-1/2x+5/2

D

Step-by-step explanation:

first let’s solve the given equation

y+1 = 2(x-3)

y+1 = 2x -6

y = 2x -7

this equation has a slope of 2

since we want a line perpendicular to this one, the slope has to be opposite and reciprocal:

2 is the same thing as 2/1 so the reciprocal is 1/2 to make this opposite we just put a negative sign in front

so the slope of our new equation is -1/2

what we have so far is: y = -1/2x + b

we know this equation has to pass thru the point (5,0) so we’ll plug in 5 for x and 0 for y so we can find b

0 = -1/2(5) +b

0 = -5/2 + b

b = 5/2

when we plug b into our equation, our final answer is

y = -1/2x + 5/2

idk

step-by-step explanation: