Tickets to a fundraiser are $14 if purchased ahead of time, and $25 if purchased at the door. The total amount raised from all ticket sales was $788. If the number of tickets purchased ahead of time was five less than the number of tickets that were purchased at the door, how many tickets were purchased at the door?

25(11)=275 which is the price of the 11 bought at the door

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step-by-step explanation:

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!