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Mathematics, 22.11.2020 06:00 hdhdhd49jdhd

Find the value of 373 using the identity (x βˆ’ y)3 = x3 βˆ’ 3x2y + 3xy2 βˆ’ y3. Show all work. Hint: 373 = (40 βˆ’ 3)3; therefore, x = 40 and y = 3.

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Find the value of 373 using the identity (x βˆ’ y)3 = x3 βˆ’ 3x2y + 3xy2 βˆ’ y3. Show all work. Hint: 373...
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