Find the point-slope equation of the line contains (-2,-3) and having slope m=4

y + 3 = 4 x (x + 2)

Step-by-step explanation:

point slope formula is y-y1 = m(x-x1)

slope intercept form is y = 4x + 5

                                       y=mx +b

                                           m=4

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐