Help pls this is a test I need a good grade

y=1.125x

Step-by-step explanation:

look for the relationship between 8 and 9 (you also can do 40 and 45). i split up 9 into 8 and 1. i saw how many times 1 went into 8. that was 8. then i did 1/8. which i got 1.125

y = 9/8x

Step-by-step explanation:

Set both up as fractions, and reduce, because this equation is in the form y = kx, both fractions reduce to the same value (proportional).

So:

9/8 = 9/8 × 5/5 = 45/40.

5/5 = 1.

45/40 = 45/40 ÷ 5/5 = 9/8.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180