Use benchmarks to estimate the sum, difference, or pruduct. 14/16 + 1/5

A. 2

B. 0

C. 1/2

D. 1


7 1/7 - 1 9/10

A. 9

B. 4

C. 5

D. 6


Use benchmarks to estimate the sum, difference, or product

7 2/7 x 3 7/9

A. 32

B. 28

C. 24

D. 21


Find the sum

3/9 + 4/9

A. 7/9

B. 7/18

C. 7/81

D. 2/3


-3/4 + 15/24

A. -3/4

B. 1/2

C. 1/8

D. -1/8


12 1/9 + 10 2/3

A. 22 1/6

B. 22 7/9

C. 22 1/9

D. 22 1/4


-1/5 + (-3/7

A. -22/35

B. - 1/3

C. 12/35

D. 4/7

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

i cant answer this, theres no table. sorry man

step-by-step explanation: