Mathematics, 21.11.2020 04:00 JustMEok9849

Help im diening please

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Answer from: sierravick123owr441

y = x + 3

Step-by-step explanation:

To know which of the equations represent the relationship between x and y, you need to substitute the x and y values into the equation. If when the equation is solved, the left-hand and right-hand side of the equation equal each other and hence the equation is true, then the equation must be correct in expressing the relationship between the x and y values. If not, then it is not correct.

As this question is only dealing with linear equations, we know that the gradient of the line is constant and hence the rate of change in x and y values is constant. Therefore, we can choose to substitute any of the given combinations of x and y values into the equation to obtain the correct equation. As it is easier to use smaller numbers for smaller calculations, we'll use the first combination of x = 1 and y = 4 .

Equation No. 1 : y = 3x + 1 where x = 1 , y = 4 and x = 2 , y = 5

( 4 ) = 3 ( 1 ) + 1

4 = 4

However, as this equation has a constant not equal to 1 in front of the x variable and hence a different gradient to the other equations, we will substitute the second combination of x and y values.

( 5 ) = 3 ( 2 ) + 1

5 = 6

Therefore, equation is false / incorrect.

Equation No. 2 : y = x + 1 where x = 1 , y = 4

( 4 ) = ( 1 ) + 1

4 = 2

Therefore, equation is false / incorrect.

Equation No. 3 : y = x + 3 where x = 1 , y = 4

( 4 ) = ( 1 ) + 3

4 = 4

Therefore, equation is true / correct.

Equation No. 4 : y = x - 3 where x = 1 , y = 4

( 4 ) = ( 1 ) - 3

4 = - 2

Therefore, equation is false / incorrect.

Answer from: Quest

the simplified form is

$\frac{x^2(2x+3)}{2(4x-3)}$

step-by-step explanation:

we want to simplify the expression,

$\frac{\frac{6x+9}{15x^2} }{\frac{16x-12}{10x^4} }$

let us change the middle bar to a normal division sign to obtain,

$\frac{6x+9}{15x^2}\div\frac{16x-12}{10x^4}$

we multiply the first fraction by the reciprocal of the second fraction to obtain,

$\frac{6x+9}{15x^2}\times \frac{10x^4}{16x-12}$

we factor to obtain,

$\frac{3(2x+3)}{3\times5\times x^2}\times \frac{2\times5\times x^2\times x^2}{4(4x-3)}$

we cancel the common factors to get,

$\frac{(2x+3)}{1}\times \frac{ x^2}{2(4x-3)}$

we simplify to get,

$\frac{x^2(2x+3)}{2(4x-3)}$

the correct answer is b

Answer from: Quest

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2

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