Find an equation for the line below

Step-by-step explanation:

you can use the equation point-slope of a line

(y-y1)= m(x-x1)

m is the slope =rise /run

to get from the lower point  on the line to the other you rise 4 units and run -6 units so m= -4/6= -2/3

now that you have the slope pick you need one point

pick any poin on the line for example (-4, -1)

now you substitute into the point-slope equation point (-4,-1) and slope -2/3

(y+1)= -2/3(x+4)

in standard form will be

y=

y=

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2