The parabola y = 3(x + 1)^2 + 3 has a vertex of

The vertex is at (h,k). For "h", swap the negative to positive and positive to negative.

So the vertex is (-1,3)

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.