Can you use ASA, AAS or both to prove the triangles congruent

The "non-included" side in AAS can be either of the two sides that are not directly between the two angles being used. Once triangles are proven congruent, the corresponding leftover "parts" that were not used in SSS, SAS, ASA, AAS and HL, are also congruent. Corresponding Parts of Congruent Triangles are Congruent.

Step-by-step explanation:

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: