Paul draws △ABC and the medians from vertices A and B. He finds that the medians intersect at a point and he labels this point X. Paul claims that point X lies outside △ABC. Do you think this is possible? Complete the explanation.

The answer is "Through which we can infer that perhaps the ABC triangles is obstinate shaped".

Step-by-step explanation:

Paul draws that ABC as well as the Median triangle from and A and B nodes. If the median passes after a certain point, and his marks the point X. Paul now says point X (i.e., a triangle's center) is outside the ABC triangle.  

They may also conclude that perhaps the ABC triangle does have an obtuse angle because the centroid is in the ring in case of even a severe triangle, that centroid is already on the right triangle in case of the triangle and cases of an obtuse-angled rectangle, the angular velocity is an outside ring.

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !

13.46

step-by-step explanation:

16.80 x .20 = 13.46