The period of a pendulum is the time the pendulum takes to swing back and forth. The function L=0.81t^2 relates the length L in feet of a pendulum to the time t in seconds that it takes to swing back and forth. A convention center has a pendulum that is 110 feet long. Find the period.

11.73seconds

Step-by-step explanation:

Given the expression of length L in feet of a pendulum to the time t in seconds that it takes to swing back and forth modeled as;

L = 0.81t²

Given

Length of the pendulum = 110feet

Required

Time (period)

Substitute the given value into the formula

L = 0.81t²

110 = 0.8t²

t² = 110/0.8

t² =137.5

t = √137.5

t = 11.73seconds

Hence the period is 11.73seconds

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

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